Utah cities, counties, school districts, colleges and special districts · 2025 pay · 16 people
How much does a data architect senior make in Utah cities, counties, school districts, colleges and special districts?
$121,987typical pay for a data architect senior in 2025
$110,601 – $138,611what most people earned
Includes everyone paid during 2025, including part-year workers. Typical pay rose 2.9% from 2024.
✓ Official data from Transparent Utah · Matches the agency's latest release · utah.gov ↗
Where data architect seniors work
Typical pay at each employer, 2025 (everyone paid).
Related jobs and the next step up
Same line of work at a different rank, by typical pay (full-year employees where we can tell).
- Data Architect$92,700 (everyone)
- Data Architect Senior (this page)$121,987 (everyone)
Highest-paid data architect seniors, 2025
- 1Carolyn B RossData Architect Senior · University of Utah$153,404
- 2Jennifer M HeningerData Architect Senior · University of Utah$147,069
- 3Robert F BirkinshawData Architect Senior · University of Utah$146,698
- 4Michael E BazaData Architect Senior · University of Utah$143,727
- 5Jianwen LaiData Architect Senior · University of Utah$136,906
Common questions
How much does a data architect senior make in Utah cities, counties, school districts, colleges and special districts?
The typical data architect senior was paid $121,987 in 2025; most earned between $110,601 and $138,611. This counts all 16 people paid, including part-year workers.
How much of the pay is overtime?
Overtime made up 0.0% of all pay for data architect seniors in 2025.
Which job titles are included?
Everyone whose payroll title is Data Architect Senior, at any level (for example "Data Architect Senior"). Part-time-schedule titles (such as "20 hours") are left out. Senior, supervising and trainee titles have their own pages.
Job titles are written out in full from the payroll's abbreviations (for example "SR CRRECTNL POLC OFCR" → "Senior Correctional Police Officer"). "Typical pay" is the median; "most earned" is the middle half. How we calculate this