Utah cities, counties, school districts, colleges and special districts · 2025 pay · 6 people
How much does a server administrator make in Utah cities, counties, school districts, colleges and special districts?
$100,224typical pay for a server administrator in 2025
$72,433 – $111,514what most people earned
Includes everyone paid during 2025, including part-year workers. Typical pay fell 9.2% from 2024.
✓ Official data from Transparent Utah · Matches the agency's latest release · utah.gov ↗
Where server administrators work
Typical pay at each employer, 2025 (everyone paid).
Related jobs and the next step up
Same line of work at a different rank, by typical pay (full-year employees where we can tell).
- Server Administrator (this page)$100,224 (everyone)
- Server Administrator Senior$103,550 (everyone)
Highest-paid server administrators, 2025
- 1Michael R McgillServer Administrator II · Salt Lake County$116,752
- 2Jace JackettaServer Administrator II · Salt Lake County$113,891
- 3Jaben E ChavezServer Administrator II · Salt Lake County$104,380
- 4Kathleen CrowServer Administrator II · Salt Lake County$96,068
- 5Clark O MercerServer Administrator II · Salt Lake County$64,555
Common questions
How much does a server administrator make in Utah cities, counties, school districts, colleges and special districts?
The typical server administrator was paid $100,224 in 2025; most earned between $72,433 and $111,514. This counts all 6 people paid, including part-year workers.
How much of the pay is overtime?
Overtime made up 0.0% of all pay for server administrators in 2025.
Which job titles are included?
Everyone whose payroll title is Server Administrator, at any level (for example "Server Administrator"). Part-time-schedule titles (such as "20 hours") are left out. Senior, supervising and trainee titles have their own pages.
Job titles are written out in full from the payroll's abbreviations (for example "SR CRRECTNL POLC OFCR" → "Senior Correctional Police Officer"). "Typical pay" is the median; "most earned" is the middle half. How we calculate this