PublicPayData

Utah cities, counties, school districts, colleges and special districts · 2025 pay · 260 people

How much does an assistant coach make in Utah cities, counties, school districts, colleges and special districts?

$3,933typical pay for a assistant coach in 2025

$1,562 – $40,218what most people earned

Includes everyone paid during 2025, including part-year workers. Typical pay fell 83.2% from 2024.

✓ Official data from Transparent Utah · Matches the agency's latest release · utah.gov ↗

Where assistant coachs work

Typical pay at each employer, 2025 (everyone paid).

Related jobs and the next step up

Same line of work at a different rank, by typical pay (full-year employees where we can tell).

  1. Coach Assistant$2,250 (everyone)
  2. Assistant Coach (this page)$3,933 (everyone)
  3. Head Coach$5,288 (everyone)

Highest-paid assistant coachs, 2025

  1. 1Kevin McgivenAssistant Coach · Utah State University$268,155
  2. 2Nicholas HowellAssistant Coach · Utah State University$265,977
  3. 3Eric HautAssistant Coach · Utah State University$226,667
  4. 4Troy MorrellAssistant Coach · Utah State University$186,304
  5. 5Shane HunterAssistant Coach · Utah State University$181,318

Common questions

How much does an assistant coach make in Utah cities, counties, school districts, colleges and special districts?

The typical assistant coach was paid $3,933 in 2025; most earned between $1,562 and $40,218. This counts all 260 people paid, including part-year workers.

How much of the pay is overtime?

Overtime made up 0.0% of all pay for assistant coachs in 2025.

Which job titles are included?

Everyone whose payroll title is Assistant Coach, at any level (for example "Assistant Coach"). Part-time-schedule titles (such as "20 hours") are left out. Senior, supervising and trainee titles have their own pages.

Job titles are written out in full from the payroll's abbreviations (for example "SR CRRECTNL POLC OFCR" → "Senior Correctional Police Officer"). "Typical pay" is the median; "most earned" is the middle half. How we calculate this